Question:medium

Equation \(x * a = b\) has in group \((G, *)\)

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In groups, equations have unique solutions.
Updated On: Jun 16, 2026
  • unique solution \(b * a^{-1}\)
  • unique solution \(a^{-1} * b\)
  • unique solution \(a^{-1} * b^{-1}\)
  • many solutions
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The Correct Option is A

Solution and Explanation

Let's consider the given scenario: the equation \(x * a = b\) in the group \((G, *)\). Our task is to determine whether there is a unique solution for \(x\), using the properties of groups. 

  1. The group \((G, *)\) satisfies certain properties: closure, associativity, the presence of an identity element, and the existence of inverse elements for every element in the group.
  2. Given the equation \(x * a = b\), we want to isolate \(x\). To do so, we multiply both sides of the equation by the inverse of \(a\) (denoted as \(a^{-1}\)) on the right:
    • Multiply both sides: \((x * a) * a^{-1} = b * a^{-1}\).
    • Utilizing associativity, we can rewrite the left-hand side as:\(x * (a * a^{-1})\).
    • Since \(a * a^{-1}\) equals the identity element \(e\) of the group, and multiplying any element by the identity does not change it, we simplify this to \(x * e = b * a^{-1}\).
    • Thus \(x = b * a^{-1}\).
  3. Therefore, in the group \((G, *)\), the equation has the unique solution \(x = b * a^{-1}\).

By understanding the properties of groups and how inverse elements function, we can derive that the correct option is

  • Unique solution: \(b * a^{-1}\)

Conclusion: The equation \(x * a = b\) in the group \((G, *)\) has a unique solution \(b * a^{-1}\).

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