Question:medium

Energy of 10 non rigid diatomic molecules at temperature T is :

Updated On: Jan 13, 2026
  • $\frac{7}{2} \, RT$
  • $70 \, K_B T$
  • $35 \, RT$
  • $35 \, K_B T$
Show Solution

The Correct Option is D

Solution and Explanation

The degrees of freedom \( f \) for a non-rigid diatomic molecule are calculated as follows:
\[f = 5 + 2(3N - 5)\]
For diatomic molecules, \( N = 2 \). Substituting this value yields:
\[f = 5 + 2(3 \times 2 - 5) = 7\]
The energy of a single molecule is expressed as:
\[\text{Energy} = \frac{f}{2} k_B T = \frac{7}{2} k_B T\]
The total energy for 10 molecules is therefore:
\[10 \times \frac{7}{2} k_B T = 35 k_B T\]

Was this answer helpful?
0


Questions Asked in JEE Main exam