Question

$E^\circ$ values of $Mg²+/Mg$ is -2.37 V, of $Zn²+/Zn$ is -0.76 V and $Fe²+/Fe$ is -0.44 V. Which of the statements is correct?

• A. Zn will reduce $Fe^{2+}$
• B. Zn will reduce $Mg^{2+}$
• C. Mg oxidises Fe
• D. Zn oxidises Fe

Hint:

$E/Mg$ is -2.37 V, of $Zn/Zn$ is -0.76 V and $Fe/Fe$ is -0.44 V. Which of the statements is correct?

Answer 1

The Correct Option is A

Step 1: Understanding the Concept
A higher negative value of standard reduction potential ($E^{\circ}$) indicates a stronger reducing power.
Step 2: Evaluation
The order of $E^{\circ}$ values (reducing power) is: $-2.37 \text{ (Mg)}>-0.76 \text{ (Zn)}>-0.44 \text{ (Fe)}$
Step 3: Answer Analysis
Mg can reduce both $Zn^{2+}$ and $Fe^{2+}$. Zn can reduce $Fe^{2+}$, but it cannot reduce $Mg^{2+}$. Iron (Fe) can neither reduce Mg nor Zn, but it can oxidise them. Thus, statement (A) is correct.
Hence, the Answer is: (A)