Step 1: Identify the reagent.
2,4-dinitrophenylhydrazine (Brady's reagent) is \(O_2N-C_6H_3(NO_2)-NH-NH_2\), a substituted hydrazine.
Step 2: Identify the carbonyl partner.
Benzaldehyde is \(C_6H_5-CHO\).
Step 3: Know the reaction.
The \(C=O\) oxygen of benzaldehyde is replaced by \(=N-NH-Ar\), where Ar is the 2,4-dinitrophenyl ring, with loss of one water molecule.
Step 4: Build the product.
The new bond is \(C_6H_5-CH=N-NH-C_6H_3(NO_2)_2\), with the two nitro groups at the 2 and 4 positions of the second ring.
Step 5: Write it clearly.
So the derivative is the 2,4-dinitrophenylhydrazone of benzaldehyde.
Answer: The structure is \(C_6H_5-CH=N-NH-C_6H_3(NO_2)_2\), where the second benzene ring carries nitro groups at positions 2 and 4 (benzaldehyde 2,4-dinitrophenylhydrazone).