Draw neat and labelled diagram of lead accumulator.

Question

Consider following reaction :
$Fe(OH)_2 + 2e^- \rightarrow Fe(s) + 2OH^-$ , $E^{\circ} = -0.88 \text{ V}$
$AgBr(s) + e^- \rightarrow Ag(s) + Br^-(aq)$ , $E^{\circ} = 0.07 \text{ V}$
Select the correct statement.
(1) $E^{\circ}_{cell} = -0.95 \text{V}$
(2) $E^{\circ}_{cell}$ is an extensive property
(3) $Fe$ is getting reduced
(4) Net cell reaction: $Fe(s) + 2OH^-(aq) + 2AgBr(s) \rightarrow Fe(OH)_2 + 2Ag(s) + 2Br^-(aq)$

Answer 1

Step 1: Understanding the Concept:
A lead accumulator (or lead-acid battery) is a secondary electrochemical cell that can be recharged. It consists of several cells connected in series.
Step 3: Detailed Explanation:
A standard diagram of a lead accumulator must include the following labels:
1. Anode (-): A series of lead ($Pb$) plates.
2. Cathode (+): A series of lead plates packed with lead dioxide ($PbO_2$).
3. Electrolyte: Aqueous solution of sulfuric acid ($H_2SO_4$) with a concentration of about 38% by mass and density of $1.28 \text{ g/mL}$.
4. Container: Usually made of hard rubber or acid-resistant plastic.
5. Separators: Insulating sheets placed between anode and cathode plates to prevent short circuits while allowing the flow of ions.
The plates are arranged in an alternating fashion and connected in parallel to increase the current capacity of the battery.
Step 4: Final Answer:
The lead accumulator consists of $Pb$ anode, $PbO_2$ cathode, and dilute $H_2SO_4$ electrolyte.

Draw neat and labelled diagram of lead accumulator.

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Solution and Explanation

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