Question:medium
$\displaystyle\lim_{x\to 0}\frac{(2+x)\sin(2+x) - 2\sin 2}{x}$ is equal to
$\displaystyle\lim_{x\to 0}\frac{(2+x)\sin(2+x) - 2\sin 2}{x}$ is equal to
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Recognise $\displaystyle\lim_{h\to 0}\frac{f(a+h)-f(a)}{h} = f'(a)$ to avoid direct computation of difficult limits.
Updated On: Apr 8, 2026
- $\sin 2$
- $\cos 2$
- 1
- $2\cos 2 + \sin 2$
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The Correct Option is D
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