Question:medium

Decarboxylation of sodium propionate leads to the formation of

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The general reaction: \(RCOONa + NaOH \xrightarrow{CaO} R-H + Na_2CO_3\). The alkane formed has one carbon less than the original carboxylic acid.

Updated On: Apr 8, 2026

methane
ethene
propanoic acid
ethane

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The Correct Option is D

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Questions Asked in MET exam

If \(f(x) = \begin{cases} x, & 0 \le x \le 1 \\ 2x - 1, & 1<x \end{cases}\), then

MET - 2019
Continuity

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