Question

de Broglie wave length associated with an electron accelerated through a potential difference \( V \) is \( \lambda \). If the accelerating potential is halved, what will be the new wavelength associated with the charged particle?

• A. \( \frac{\lambda}{\sqrt{2}} \)
• B. \( \frac{\lambda}{2} \)
• C. \( 2\lambda \)
• D. \( \sqrt{2}\lambda \)

Hint:

De Broglie wavelength varies inversely with square root of accelerating potential.

Answer 1

The Correct Option is D