Question

D(+) glucose reacts with hydroxylamine and yields an oxime. The structure of the oxime would be:

• A.
• B.
• C.
• D.

Answer 1

The Correct Option is C

When D(+) glucose reacts with hydroxylamine, it forms an oxime. Let's break down the steps involved in this reaction:

1. Understanding the Reaction:
   • D(+) glucose is an aldose sugar with an aldehyde group at the first carbon.
   • When D(+) glucose reacts with hydroxylamine (NH₂OH), a condensation reaction occurs. The aldehyde group forms a double bond with the nitrogen atom from the hydroxylamine, producing an oxime.
2. Formation of Oxime:
   • In the reaction, the carbonyl oxygen of glucose is replaced by the nitrogen from NH₂OH, leading to the formation of the oxime group, which is represented as =N-OH.
3. Correct Structure Identification:
   • From the given options, we need to identify the structure that shows the oxime formation correctly at the aldehyde group.
   • The option showing the conversion of the aldehyde group (C=O) of D(+) glucose into an oxime group (C=NOH) is the correct structure.

Therefore, the correct structure of the oxime from D(+) glucose reacting with hydroxylamine is:

This structure shows the key transformation of the aldehyde group into an oxime upon reaction with hydroxylamine.