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Inverse Trigonometric Functions
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\( \cos^{-1}\left(\cos\left(\frac{7\pi}{5}\right)\right) = \)
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For \( \cos^{-1}(\cos \theta) \), if \( \theta \) is in the 3rd or 4th quadrant, use the formula \( 2\pi - \theta \) to bring it back to the principal range.
KEAM - 2014
KEAM
Updated On:
May 6, 2026
\( \frac{3\pi}{5} \)
\( \frac{2\pi}{5} \)
\( \frac{-7\pi}{5} \)
\( \frac{7\pi}{5} \)
\( \frac{-2\pi}{5} \)
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The Correct Option is
A
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Top Questions on Inverse Trigonometric Functions
The principal value of
\( \cot^{-1} \left( -\frac{1}{\sqrt{3}} \right) \)
is:
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The principal branch of $\cos^{-1} x$ is:
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The principal value of
\( \cot^{-1} \left( -\frac{1}{\sqrt{3}} \right) \)
is:
CBSE Class XII - 2025
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Assertion (A): The set of values of $\sec^{-1} \left( \frac{\sqrt{3}}{2} \right)$ is a null set.
Reason (R): $\sec^{-1}x$ is defined for $x \in \mathbb{R} - (-1, 1)$.
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Mathematics
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