Question:medium
\(\cos^{-1}\{\cos 2\cot^{-1}(\sqrt{2} - 1)\}\) is equal to
\(\cos^{-1}\{\cos 2\cot^{-1}(\sqrt{2} - 1)\}\) is equal to
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\(\cot^{-1}(\sqrt{2} - 1) = \frac{3\pi}{8}\) and \(\cos^{-1}(\cos \theta) = \theta\) for \(\theta \in [0, \pi]\).
Updated On: Apr 7, 2026
- \(\sqrt{2} - 1\)
- \(\frac{\pi}{4}\)
- \(\frac{3\pi}{4}\)
- 0
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The Correct Option is C
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