We are given the function:
\[
f(x, y) = (x + y - 1)^2 + (x + y)^2
\]
Let \( z = x + y \). Then:
\[
f(x, y) = (z - 1)^2 + z^2 = z^2 - 2z + 1 + z^2 = 2z^2 - 2z + 1
\]
Now minimize:
\[
g(z) = 2z^2 - 2z + 1
\]
This is a quadratic function. The minimum occurs at:
\[
z = \frac{-(-2)}{2 \cdot 2} = \frac{2}{4} = \frac{1}{2}
\]
So, the minimum value of the original function occurs when:
\[
x + y = \frac{1}{2}
\]
All points \( (x, y) \in \mathbb{R}^2 \) such that \( x + y = \frac{1}{2} \) will minimize the function. This is a line in \( \mathbb{R}^2 \), and therefore the set \( S \) is infinite.