Consider the following redox reaction in basic medium. \( x\text{Cr(OH)}_3 + y(\text{IO}_3)^- + z(\text{OH})^- \rightarrow a(\text{CrO}_4)^{2-} + b(\text{I})^- + c(\text{H}_2\text{O}) \). The incorrect option about it is
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When balancing redox reactions in a basic medium:
1. Balance atoms other than O and H.
2. Balance O atoms by adding \(H_2O\).
3. Balance H atoms by adding \(H^+\).
4. Balance charge by adding \(e^-\).
5. Add a number of \(OH^-\) ions to both sides equal to the number of \(H^+\) ions.
6. Combine \(H^+\) and \(OH^-\) to form \(H_2O\) and simplify the equation.