Question

Consider the following reaction ${ ->[H_2][pd-BaSO_4] 'A'}$ The product 'A' is -

• A. ${C_6 H_5 OH}$
• B. ${C6H5COCH3 }$
• C. ${ C6H5Cl }$
• D. ${C6H5CHO }$

Answer 1

The Correct Option is D

To solve this question, we need to consider the given reaction:

${ -\rightarrow[H_2][\text{pd-BaSO}_4] \text{ 'A'}}$

We have four options for the product 'A':

1. ${C_6H_5OH}$
2. ${C_6H_5COCH_3}$
3. ${C_6H_5Cl}$
4. ${C_6H_5CHO}$

This reaction involves catalytic hydrogenation using ${\text{H}_2/\text{pd-BaSO}_4}$. This specific combination is used in the Rosenmund Reduction, which reduces acyl chlorides (acid chlorides) to corresponding aldehydes.

The correct answer is ${C_6H_5CHO}$, which is benzaldehyde. The reaction can be illustrated as:

\text{C}_6\text{H}_5\text{-CO-Cl} + \text{H}_2 \xrightarrow[\text{H}_2/\text{pd-BaSO}_4] \text{C}_6\text{H}_5\text{CHO}

Here is the reasoning for the other options:

• ${C_6H_5OH}$ (phenol) is unrelated to the given reaction process.
• ${C_6H_5COCH_3}$ (acetophenone) is a ketone, originating from different synthesis routes.
• ${C_6H_5Cl}$ (chlorobenzene) is derived from aromatic electrophilic substitution reactions.

Conclusion: The product 'A' in the given reaction is benzaldehyde, symbolized as ${C_6H_5CHO}$. This is consistent with the typical reaction observed in Rosenmund Reduction.