To determine the total number of elements in the set \( A = (L_1 \cap L_2) \cup (L_2 \cap L_3) \cup (L_3 \cap L_1) \), we need to find the intersection points of the lines \( L_1 \), \( L_2 \), and \( L_3 \).
Step 1: Equation of Line \( L_1 \)
The equation of line \( L_1 \) is given as:
\(5x - 2y = 1\)
This can be rewritten to find the slope-intercept form:
\(y = \frac{5}{2}x - \frac{1}{2}\)
Step 2: Equation of Line \( L_2 \)
Line \( L_2 \) passes through the points \( (0, 1) \) and \( (100, 101) \). The slope \( m_2 \) is:
\(m_2 = \frac{101 - 1}{100 - 0} = 1\)
The equation of the line passing through \( (0, 1) \) with a slope of 1 is:
\(y = x + 1\)
Step 3: Equation of Line \( L_3 \)
Line \( L_3 \) is parallel to the vector \(-\hat{i} + 2\hat{j}\), meaning the slope is:
\(m_3 = \frac{2}{-1} = -2\)
Since it passes through \( (1, 11) \), the equation is:
\(y - 11 = -2(x - 1)\)
Simplifying, we get:
\(y = -2x + 13\)
Step 4: Finding Intersection Points
Equate the equations: \(\frac{5}{2}x - \frac{1}{2} = x + 1\)
Simplifying, we get:
\(x = \frac{3}{2}, \, y = \frac{5}{2}\)
Equate the equations: \(x + 1 = -2x + 13\)
Simplifying, we get:
\(x = 4, \, y = 5\)
Equate the equations: \(-2x + 13 = \frac{5}{2}x - \frac{1}{2}\)
Simplifying, we find:
\(x = 2, \, y = 9\)
Conclusion: Each pair of lines intersects at a unique point. Thus, the total number of distinct intersection points (elements of \( A \)) is 3.
The correct answer is: 3.
In a △ABC, suppose y = x is the equation of the bisector of the angle B and the equation of the side AC is 2x−y = 2. If 2AB = BC and the points A and B are respectively (4, 6) and (α, β), then α + 2β is equal to: