Instead of quoting a formula for cycles, we can just try placing fewer and fewer guards and see what breaks. The diagram has 5 junctions joined in a ring: going around, top, left shoulder, bottom left, bottom right, right shoulder, and back to top, with 5 walkways total.
- Trying 1 guard: a single junction only touches 2 of the 5 walkways, so 3 walkways would have no guard nearby. Not enough.
- Trying 2 guards: two junctions touch at most 4 walkway ends between them (2 walkways each), but the ring has 5 walkways, and however the 2 guards are placed, at least one walkway ends up with neither of its junctions guarded. Not enough.
- Trying 3 guards: place guards at the top junction, the left shoulder junction, and the bottom right junction. Walking through the 5 walkways one by one: top-left shoulder has both ends guarded, top-right shoulder has the top guarded, left shoulder-bottom left has the left shoulder guarded, bottom left-bottom right has the bottom right guarded, and bottom right-right shoulder has the bottom right guarded. Every single walkway has at least one guarded end.
- Could 3 be beaten: since 2 guards were shown to always miss a walkway, 3 is the smallest number that works.
So the minimum number of guards is 3, confirmed by direct trial rather than a formula, which matches option (B).
Let's summarize:
- The walkway diagram is a closed ring of 5 junctions and 5 walkways.
- With only 1 or 2 guards, some walkway is always left unwatched.
- Placing guards at 3 well chosen junctions, alternating around the ring, covers every walkway.
The correct answer is 3 guards.