Question:medium

Consider a reversible heat engine with a thermal efficiency of 55%. The engine is reversed and operated as a heat pump between the same temperature reservoirs.
If the heat supplied from the low temperature reservoir is 45 kJ/cycle, then the absolute value of heat rejected is ______ kJ/cycle (answer in integer).

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First get T_L/T_H from the engine efficiency, then reuse the same ratio for the heat pump's Q_L/Q_H.
Updated On: Jul 28, 2026
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Correct Answer: 100

Solution and Explanation

A reversible engine and a reversible heat pump running between the same two reservoirs share the exact same temperature ratio, because reversibility fixes $Q_L/Q_H = T_L/T_H$ regardless of which direction the cycle runs. This lets us reuse the efficiency information from the engine mode directly in the heat pump mode.

As an engine, $\eta = 1 - T_L/T_H = 0.55$, so $T_L/T_H = 0.45$. This is the same ratio that connects the heat pump's cold-side heat intake $Q_L$ and hot-side heat rejection $Q_H$, since $Q_L/Q_H = T_L/T_H$.

Now with the engine reversed into a heat pump, the heat absorbed from the low temperature reservoir is given as $Q_L = 45$ kJ/cycle. Rearranging the ratio gives $Q_H = Q_L \times (T_H/T_L) = 45 / 0.45$.

This works out to exactly $100$ kJ/cycle, so the heat pump rejects $100$ kJ/cycle to the high temperature reservoir, which is the required answer.

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