Step 1: Count the ways to choose which day is sunny.
Out of 4 days, exactly one day is sunny and the other three are cloudy.
There are $\binom{4}{1} = 4$ ways to pick which single day is the sunny one.
Step 2: Find the probability of one such arrangement.
Cloudy and sunny each have probability $0.5$, and the days are independent.
Any one specific sequence of 3 cloudy days and 1 sunny day has probability $(0.5)^3 \times (0.5)^1 = (0.5)^4 = 1/16$.
Step 3: Add up all the arrangements.
Each of the 4 possible positions for the sunny day gives this same probability $1/16$, and these outcomes do not overlap.
So the total probability is $4 \times 1/16 = 1/4$.
Final Answer:
Three cloudy days and one sunny day out of four occur with probability 1/4, so option (A) is correct.
\[ \boxed{P = \dfrac{1}{4}} \]