Step 1: Understanding the Topic:
This problem focuses on the qualitative analysis of organic compounds. It uses specific chemical tests (2,4-DNP, Fehling's, and Sodium Bicarbonate) to determine the functional groups of unknown molecules. It also requires understanding the oxidation of alkyl/acyl side chains in aromatic compounds. Deciphering these tests is essential for identifying substances in organic chemistry labs.
Step 2: Key Formulas and Approach:
The approach involves translating each chemical test into a functional group:
2,4-DNP Positive $\rightarrow$ Carbonyl group present (Aldehyde or Ketone).
Fehling's Negative $\rightarrow$ Not an aliphatic aldehyde (likely a Ketone).
NaHCO$_3$ Positive $\rightarrow$ Carboxylic acid group present.
Oxidation of $Ar-R$ or $Ar-CO-R$ $\rightarrow$ $Ar-COOH$.
Step 3: Detailed Explanation:
Identify P: The molecular formula $C_8H_8O$ indicates a high degree of unsaturation (likely a benzene ring). A positive 2,4-DNP test confirms a carbonyl. A negative Fehling's test indicates a ketone rather than an aldehyde. Acetophenone ($C_6H_5COCH_3$) perfectly fits these observations and the formula $C_8H_8O$.
Identify Q: Strong oxidation of acetophenone with chromic acid ($H_2CrO_4$) cleaves the side chain and oxidizes the carbon attached to the ring to its highest state.
\[ C_6H_5COCH_3 \xrightarrow{[O]} C_6H_5COOH \]
The product $Q$ is thus Benzoic Acid.
Verification: Benzoic acid is a carboxylic acid, so it will react with sodium bicarbonate to release carbon dioxide gas, causing the observed effervescence.
Step 4: Final Answer:
P is acetophenone and Q is benzoic acid, matching option (A).