Question

Compound $A, C_8H_{10}O$, is found to react with $NaOI$ (produced by reacting $Y$ with $NaOH$) and yields a yellow precipitate with characteristic smell. $A$ and $Y$ are respectively

• A.

  

• B.

  

• C.

  

• D.

  

Answer 1

The Correct Option is C

To solve this problem, we need to identify the compound $A, C_8H_{10}O$, which reacts with $NaOI$ to yield a yellow precipitate with a characteristic smell. The precipitate with a strong odor is indicative of iodoform, which is a key clue in determining the compounds involved. This specific reaction is known as the iodoform test, which is positive for methyl ketones or secondary alcohols with a methyl group adjacent to the hydroxyl group.

1. The yellow precipitate is iodoform (CHI_3), which suggests that compound $A$ must have the substructure of either a methyl ketone or a secondary alcohol with a methyl group on the carbon adjacent to the -OH group.
2. The compound $Y$ reacts with $NaOH$ to produce $NaOI$. The common reagent used for this is iodine, $I_2$. This tells us that $Y$ is iodine.
3. For $C_8H_{10}O$ to be a methyl ketone or a specific alcohol suitable for the iodoform test, it is most likely benzyl alcohol or acetophenone (since we are working in an aromatic context due to the presence of a benzene ring in the choices).
4. Upon inspection of the options provided, the compound acetophenone and iodine fit our scenario perfectly. Acetophenone has the correct formula and structure to yield iodoform when reacted with $NaOI$.

Therefore, the correct choice involves acetophenone as compound $A$, and iodine as $Y$.

Hence, the compounds $A$ and $Y$ are acetophenone and iodine respectively.