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Common tangent to circle \(x^2+y^2=4\) and parabola \(y^2=8\sqrt2 x\) is \(y=mx+c\). Then \(\sqrt{m+c^2}=\)

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Common tangents always satisfy both curve tangency equations simultaneously.

Updated On: Jun 22, 2026

4
3
2
1 \bigskip

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The Correct Option is A

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