Step 1: Recall the general structure of amino acids.
\[
R-CH(NH_2)-COOH
\]
If the carbon atom is attached to four different groups, the amino acid becomes optically active.
Step 2: Examine glycine.
For glycine,
\[
R=H
\]
Hence its structure is
\[
H_2N-CH_2-COOH
\]
The central carbon is attached to:
\[
H,\ H,\ NH_2,\ COOH
\]
Since two substituents are identical hydrogen atoms, the carbon atom is not chiral.
Therefore glycine is optically inactive.
Step 3: Examine the remaining amino acids.
Alanine, leucine and isoleucine possess asymmetric carbon atoms and therefore are optically active.
Step 4: Final answer.
\[
{\text{Glycine}}
\]