In an isothermal free expansion into a vacuum, the gas performs no work as the external pressure is zero. Consequently, the internal energy of the ideal gas remains constant \((\Delta U=0)\) due to the isothermal process. Applying the first law of thermodynamics, \(\Delta U = q + w\), where q represents heat absorbed and w represents work done. Given that \(\Delta U=0\) and \(w=0\), it follows that the heat absorbed (q) is also zero.