Excess chlorine Cl2 in drinking water is removed by treating it with sulphur dioxide SO2 in the presence of water. In this redox change:
Cl2_{(aq)} + SO2_{(aq)} + 2H2O_{(l)} -> 2Cl^-_{(aq)} + SO4^{2-}_{(aq)} + 4H^+_{(aq)}
In words: Chlorine reacts with sulphur dioxide in water to form chloride ions, sulfate ions and hydrogen ions.
The products formed in the following reaction, A and B, are:
