Charges of $2\mu C$ and $-3\mu C$ are placed at two points A and B separated by distance of 1 m. The distance of the point from A where net potential is zero is ______.
Show Hint
The internal zero-potential point always lies closer to the charge with the SMALLER magnitude. $2\mu\text{C}$ is smaller than $3\mu\text{C}$, so $x$ must be less than $0.5$ m. Option (c) is the only logical choice!
Step 1: Understanding the Concept:
Electric potential $V = \frac{kQ}{r}$. We need the point where $V_A + V_B = 0$. Step 2: Formula Application:
Let the distance from A be $x$. The distance from B is $(1 - x)$.
$\frac{k(2 \times 10^{-6})}{x} + \frac{k(-3 \times 10^{-6})}{1-x} = 0$. Step 3: Explanation:
$\frac{2}{x} = \frac{3}{1-x} \implies 2(1-x) = 3x$.
$2 - 2x = 3x \implies 5x = 2 \implies x = 0.4$ m. Step 4: Final Answer:
The distance from point A is 0.4 m.