Question:medium
\(CH_4(g)+4Cl_2(g)\rightarrow CCl_4(l)+4HCl(g)\). In the above reaction, the change of oxidation state of carbon is
\(CH_4(g)+4Cl_2(g)\rightarrow CCl_4(l)+4HCl(g)\). In the above reaction, the change of oxidation state of carbon is
Show Hint
In \(CH_4\), carbon is \(-4\). In \(CCl_4\), carbon is \(+4\).
Updated On: Apr 29, 2026
- From \(+4\) to \(-4\)
- From \(+1\) to \(+4\)
- From \(-4\) to \(+4\)
- From \(-1\) to \(+1\)
- From \(-4\) to \(-1\)
Show Solution
The Correct Option is C
Solution and Explanation
Was this answer helpful?
0
Top Questions on Oxidation Number And Oxidation States
- What is the number of unpaired electrons in Lutetium (Lu) in the +3 oxidation state?
- MHT CET - 2025
- Chemistry
- Oxidation Number And Oxidation States
- In the reaction \( 2\text{NaOH} + \text{Cl}_2 \rightarrow \text{NaCl} + \text{NaOCl} + \text{H}_2\text{O} \), what is the oxidation state of chlorine in sodium hypochlorite (NaOCl)?
- BITSAT - 2025
- Chemistry
- Oxidation Number And Oxidation States
- In which compound does Mn (Manganese) have its highest oxidation state?
- BCECE - 2025
- Chemistry
- Oxidation Number And Oxidation States
- Given below are two statements :
Statement I : The higher oxidation states are more stable down the group among transition elements unlike p-block elements.
Statement II : Copper can not liberate hydrogen from weak acids.
In the light of the above statements, choose the correct answer from the options given below- JEE Main - 2024
- Chemistry
- Oxidation Number And Oxidation States
- Want to practice more? Try solving extra ecology questions todayView All Questions
