Question

Calculate the temperature of 2 moles of gas occupying a volume of 5.0 liters at 24.6 atmospheres?
(\(R = 0.0821\) L atm K\(^{-1}\) mol\(^{-1}\))

• A. \(476^{\circ}\)C
• B. \(480^{\circ}\)C
• C. \(440^{\circ}\)C
• D. \(450^{\circ}\)C

Hint:

Use \(PV=nRT\) and convert the Kelvin result to Celsius.

Answer 1

The Correct Option is A

Step 1: Plan:
Work out $nR$ first, then divide.

Step 2: Steps:
$nR = 2\times0.0821 = 0.1642$ L atm K$^{-1}$. $PV = 24.6\times5.0 = 123$ L atm.
$T = \frac{123}{0.1642} \approx 749$ K, and $749 - 273 = 476^{\circ}$C.

Final Answer:
The temperature is about $476^{\circ}$C, option (A). \[ \boxed{476^{\circ}\text{C}} \]