Step 1: Energy balance:
Temperature stays fixed, so the gas has the same internal energy at the start and end. All the work done on it by the surroundings must leave as heat.
Step 2: Numbers:
Work done on gas = pressure $\times$ volume decrease = $4\text{ bar}\times 15\text{ dm}^3 = 60\text{ bar dm}^3$.
Since 1 bar dm$^3$ = 100 J, this is 6000 J = 6.0 kJ.
Heat released = work received = 6.0 kJ, which is option (D).
Final Answer:
The system releases 6.0 kJ of heat.
\[ \boxed{6.0\text{ kJ}} \]