Question:medium

Calculate the mean of the following data :
Class :4 – 67 – 910 – 1213 – 15
Frequency :54910

Updated On: Jan 13, 2026
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Solution and Explanation

Step 1: Determine Class Midpoints
The midpoints ($x_i$) are computed by averaging the lower and upper limits of each class:
\[x_1 = \frac{4 + 6}{2} = 5, \quad x_2 = \frac{7 + 9}{2} = 8, \quad x_3 = \frac{10 + 12}{2} = 11, \quad x_4 = \frac{13 + 15}{2} = 14.\]
Step 2: Calculate Midpoint-Frequency Products
Create the following table:
\[\begin{array}{|c|c|c|c|}\hline\text{Class} & \text{Frequency } (f_i) & \text{Midpoint } (x_i) & f_i x_i \\\hline4 - 6 & 5 & 5 & 25 \\7 - 9 & 4 & 8 & 32 \\10 - 12 & 9 & 11 & 99 \\13 - 15 & 10 & 14 & 140 \\\hline\end{array}\]
Step 3: Sum Frequencies and Midpoint-Frequency Products
\[\sum f_i = 5 + 4 + 9 + 10 = 28.\]
\[\sum f_i x_i = 25 + 32 + 99 + 140 = 296.\]
Step 4: Compute the Mean
The mean is calculated using the formula:
\[\text{Mean} = \frac{\sum f_i x_i}{\sum f_i}.\]
Substituting the calculated values:
\[\text{Mean} = \frac{296}{28} = 10.57.\]
Correct Answer: Mean = 10.57

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