List of top Mathematics Questions on Statistics asked in CBSE Class X

If the mean of first n natural numbers is \(\frac{6n}{11}\), then n is

Find the mean and the mode of the following frequency distribution :

The median and mode of a distribution are $25.2$ and $26.1$ respectively. The mean of the distribution is :

The mean and median of a frequency distribution are 43 and 43.4 respectively. The mode of the distribution is :

Assertion (A) : The mean of first 'n' natural numbers is \(\frac{n - 1}{2}\).
Reason (R) : The sum of first 'n' natural numbers is \(\frac{n(n + 1)}{2}\).

If the mean and mode of a data are 12 and 21 respectively, then its median is :

Find the mean and the mode for the following frequency distribution :

Assertion (A) : If the value of mode and mean for a distribution is 50 and 56 respectively, then the value of median is 54.
Reason (R) : Median = \(\frac{1}{3}\) (Mode - 2 Mean)

Assertion (A) : Median of a data is the value of \(\frac{N}{2}\), where N represents sum of all frequencies.
Reason (R) : Median divides the whole distribution in two equal parts.

If the median of the following distribution is 32.5, then find the values of x and y.

Find mean and mode of the following frequency distribution :

Assertion (A) : The mean of first 'n' natural numbers is \( \frac{n - 1}{2} \).
Reason (R) : The sum of first 'n' natural numbers is \( \frac{n(n + 1)}{2} \).

An SBI health insurance agent found the following data for distribution of ages of 100 policy holders. Find the modal age and median age of the policy holders.

Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

The median of the following data is 32.5, find the missing frequencies \(x\) and \(y\) :

If for a data, median is 5 and mode is 4, then mean is equal to :

While calculating mean of a grouped frequency distribution, step deviation method was used \(u = \frac{x-a}{h}\). It was found that \(\bar{x} = 64\), \(h = 5\) and \(a = 62.5\). The value of \(\bar{u}\) is

The mean of the following distribution is 53. Find the missing frequency p.

Hence, find mode of the distribution.}

Compute median of the following data :

The mean and median of a frequency distribution are 43 and 43.4 respectively. The mode of the distribution is :

If the mean and mode of a data are 12 and 21 respectively, then its median is :

The mean of the following frequency distribution is 35. Find the values of x and y, if the sum of frequencies is 25 :

If the mean and mode of a data are 12 and 21 respectively, then its median is :

The marks obtained by 80 students of class X in a mock test of Mathematics are given below in the table. Find median and the mode of the data :

The upper limit of the median class of the above data is :