List of top Mathematics Questions on Statistics asked in CBSE Class X

An SBI health insurance agent found the following data for distribution of ages of 100 policy holders. Find the modal age and median age of the policy holders.

Assertion (A) : The mean of first 'n' natural numbers is \( \frac{n - 1}{2} \).
Reason (R) : The sum of first 'n' natural numbers is \( \frac{n(n + 1)}{2} \).

If the median of the following distribution is 32.5, then find the values of x and y.

Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

Find mean and mode of the following frequency distribution :

The median of the following data is 32.5, find the missing frequencies \(x\) and \(y\) :

If for a data, median is 5 and mode is 4, then mean is equal to :

While calculating mean of a grouped frequency distribution, step deviation method was used \(u = \frac{x-a}{h}\). It was found that \(\bar{x} = 64\), \(h = 5\) and \(a = 62.5\). The value of \(\bar{u}\) is

The mean of the following distribution is 53. Find the missing frequency p.

Hence, find mode of the distribution.}

Compute median of the following data :

The mean and median of a frequency distribution are 43 and 43.4 respectively. The mode of the distribution is :

If the mean and mode of a data are 12 and 21 respectively, then its median is :

The mean of the following frequency distribution is 35. Find the values of x and y, if the sum of frequencies is 25 :

If the mean and mode of a data are 12 and 21 respectively, then its median is :

The marks obtained by 80 students of class X in a mock test of Mathematics are given below in the table. Find median and the mode of the data :

The upper limit of the median class of the above data is :

The mode of the following data is 3.286. Find the mean and median of the above data.

Find 'mean' and 'mode' of the following data : Frequency Distribution Table

Class	0 – 15	15 – 30	30 – 45	45 – 60	60 – 75	75 – 90
Frequency	11	8	15	7	10	9

To calculate mean of grouped data, Rahul used assumed mean method. He used \(d = (x - A)\), where \(A\) is the assumed mean. Then \(\bar{x}\) is equal to

Find the ‘mean’ and ‘mode’ marks of the following data:

Calculate the mean of the following data :

Class :	4 – 6	7 – 9	10 – 12	13 – 15
Frequency :	5	4	9	10

Marks :	Below 10	Below 20	Below 30	Below 40	Below 50
Number of Students :	3	12	27	57	75

For the above distribution, the modal class is :

The mean and median of a statistical data are 21 and 23 respectively. The mode of the data is: