Question:medium
Calculate the entropy change in the following. Given latent heat of steam is \(540\ \text{cal/g}\), latent heat of ice is \(80\ \text{cal/g}\).
A. \(10g\) of water at \(100^\circ C\) converted to steam at same temperature,
B. \(20g\) of water at \(100^\circ C\) converted to steam at same temperature,
C. \(1g\) of ice at \(0^\circ C\) converted into water at \(0^\circ C\),
D. \(10g\) of ice at \(0^\circ C\) converted into water at \(0^\circ C\).
Calculate the entropy change in the following. Given latent heat of steam is \(540\ \text{cal/g}\), latent heat of ice is \(80\ \text{cal/g}\).
A. \(10g\) of water at \(100^\circ C\) converted to steam at same temperature,
B. \(20g\) of water at \(100^\circ C\) converted to steam at same temperature,
C. \(1g\) of ice at \(0^\circ C\) converted into water at \(0^\circ C\),
D. \(10g\) of ice at \(0^\circ C\) converted into water at \(0^\circ C\).
A. \(10g\) of water at \(100^\circ C\) converted to steam at same temperature,
B. \(20g\) of water at \(100^\circ C\) converted to steam at same temperature,
C. \(1g\) of ice at \(0^\circ C\) converted into water at \(0^\circ C\),
D. \(10g\) of ice at \(0^\circ C\) converted into water at \(0^\circ C\).
Show Hint
For phase change at constant temperature, use \(\Delta S=\frac{mL}{T}\).
Updated On: May 19, 2026
- B \(>\) A \(>\) D \(>\) C
- A \(>\) B \(>\) C \(>\) D
- A \(<\) B \(<\) C \(<\) D
- A \(>\) B \(<\) C \(>\) D
Show Solution
The Correct Option is A
Solution and Explanation
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