To determine the impact on the transmission range of a TV tower when its height is increased, we begin with the relationship between the height of the tower and its transmission range. The transmission range of a TV tower is directly proportional to the square root of its height. Mathematically, this is expressed as:
R \propto \sqrt{h}
Let the original height of the tower be h and the original range be R. The relationship can be given by:
R = k \sqrt{h}
where k is the proportionality constant.
When the height of the tower is increased by 21%, the new height h' is:
h' = h + 0.21h = 1.21h
The new transmission range R' is:
R' = k \sqrt{h'} = k \sqrt{1.21h}
Simplifying further:
R' = k \sqrt{1.21} \sqrt{h} = R \cdot \sqrt{1.21}
We need to calculate \sqrt{1.21}:
\sqrt{1.21} \approx 1.1
Therefore, the new range R' can be written as:
R' = 1.1R
The percentage increase in range is then given by:
\left(\frac{R' - R}{R} \times 100\%\right) = (1.1R - R) / R \times 100\% = 0.1 \times 100\% = 10\%
Thus, when the height of the TV tower is increased by 21%, its transmission range increases by 10%.
Match List-I with List-II:
| List-I (Modulation Schemes) | List-II (Wave Expressions) |
|---|---|
| (A) Amplitude Modulation | (I) \( x(t) = A\cos(\omega_c t + k m(t)) \) |
| (B) Phase Modulation | (II) \( x(t) = A\cos(\omega_c t + k \int m(t)dt) \) |
| (C) Frequency Modulation | (III) \( x(t) = A + m(t)\cos(\omega_c t) \) |
| (D) DSB-SC Modulation | (IV) \( x(t) = m(t)\cos(\omega_c t) \) |
Choose the correct answer: