(a) Force on a Current-Carrying Conductor: A simple setup (as depicted in the figure) demonstrates the force acting on conductor AB. A magnet (with N and S poles) provides the magnetic field, and a current flows through conductor AB. Placing a current-carrying conductor within a magnetic field results in a force, arising from the interaction between the conductor's current and the magnetic field. This force is calculated using: \[ F = BIL \sin \theta \] where:
\( F \) represents the force on the conductor,
\( B \) signifies the magnetic field strength,
\( I \) denotes the current in the conductor,
\( L \) is the length of the conductor within the magnetic field,
\( \theta \) is the angle between the magnetic field and the current's direction.
(b) Force Direction Reversal: The force's direction on the conductor can be inverted by either:
1. Reversing the current's direction in conductor AB.
2. Reversing the magnetic field's direction (by swapping the magnet's poles).
Three long straight wires carrying current are arranged mutually parallel as shown in the figure. The force experienced by \(15\) cm length of wire \(Q\) is ________. (\( \mu_0 = 4\pi \times 10^{-7}\,\text{T m A}^{-1} \)) 