Question:medium

Benzene nitrile on reaction with reagent (A) gave product (X). In another reaction with reagent (B) gave product (Y). \(X\) and \(Y\) both form oxime but only \(Y\) gets oxidized with ammoniacal silver nitrate solution. The correct reagents \(A\) and \(B\) respectively are \[ \begin{aligned} \text{I. }&\mathrm{CH_3CH_2MgBr,\ H_2O} \qquad;\qquad \mathrm{DIBAL\!-\!H,\ H_2O} \text{II. }&(\mathrm{CH_3CH_2})_2\mathrm{Cd} \qquad;\qquad \mathrm{SnCl_2+HCl,\ H_2O} \text{III. }&\mathrm{CH_3CH_2MgBr,\ H_2O} \qquad;\qquad \mathrm{SnCl_2+HCl,\ H_2O} \text{IV. }&(\mathrm{CH_3CH_2})_2\mathrm{Cd} \qquad;\qquad \mathrm{DIBAL\!-\!H,\ H_2O} \end{aligned} \] The correct answer is

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Important reactions of nitriles: \[ \boxed{ \begin{aligned} \mathrm{RCN} &\xrightarrow{\mathrm{RMgX}} \text{Ketone} \mathrm{RCN} &\xrightarrow{\mathrm{DIBAL\!-\!H}} \text{Aldehyde} \mathrm{RCN} &\xrightarrow{\mathrm{SnCl_2/HCl}} \text{Aldehyde (Stephen reaction)} \end{aligned} } \]
Updated On: Jul 15, 2026
  • III, IV
  • I, II
  • I, III
  • II, IV
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The Correct Option is C

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