Question:easy

At critical angle, the angle of refraction is

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Remember: Denser to Rarer only! You cannot have a critical angle or total internal reflection if light is moving from a rarer medium (like air) to a denser medium (like water), as the light will always bend towards the normal in that case.
  • $45^\circ$
  • $90^\circ$
  • $120^\circ$
  • $180^\circ$
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The Correct Option is B

Solution and Explanation

1. Definition of Critical Angle ($i_c$): When light travels from a denser medium (refractive index $n_1$) to a rarer medium (refractive index $n_2$), it bends away from the normal. As the angle of incidence ($i$) increases, the angle of refraction ($r$) also increases.

2. The Condition at $i_c$: The critical angle is defined as the angle of incidence for which the refracted ray grazes the boundary surface between the two media. This means the refracted ray is perpendicular to the normal.

3. Mathematical Proof using Snell's Law: $$n_1 \sin i_c = n_2 \sin r$$ At the critical angle, the light is at the limit of escaping the denser medium. For this to happen, $\sin r$ reaches its maximum value of $1$. $$\sin r = 1 \implies r = 90^\circ$$ If the angle of incidence exceeds the critical angle, refraction is no longer possible, and the light undergoes total internal reflection.
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