At a given place, to increase the number of oscillations made by a simple pendulum in one minute from 72 to 90, the length of the pendulum is to be decreased by
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For a simple pendulum, the relationship between frequency ($f$) and length ($L$) is $f \propto 1/\sqrt{L}$. This implies $L \propto 1/f^2$. This proportionality is very useful for ratio-based problems, as you don't need to use the full formula with $g$ and $2\pi$.