Question:medium

At 700K, the value of $K_{c}$ for the following reaction is 64: $H_{2}(g)+I_{2}(g)\rightleftharpoons2HI(g)$. If 0.5 mole of $H_{2}(g)$ and 0.5 mole of $I_{2}(g)$ were mixed at 700K and allowed to reach equilibrium, the amount of HI formed by mole is:

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When $\Delta n = 0$ (like in the $HI$ synthesis), $K_c = K_p = K_x$. In these cases, you don't need to know the volume of the container—you can work directly with moles!
Updated On: May 20, 2026
  • 0.40
  • 0.80
  • 0.50
  • 0.66
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The Correct Option is B

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