Question:medium

Assertion (A) : If the value of mode and mean for a distribution is 50 and 56 respectively, then the value of median is 54.
Reason (R) : Median = \(\frac{1}{3}\) (Mode - 2 Mean)

Show Hint

An easy way to memorize the empirical relation is by counting the syllables/letters or matching coefficients:
\[ \text{Mode} = 3\ \text{Median} - 2\ \text{Mean} \]
Think of it as "3 Medians minus 2 Means equals the Mode".
Note that the number 3 is paired with "Median" (the longer word) and the number 2 is paired with "Mean" (the shorter word).
Updated On: Jul 7, 2026
  • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
  • Both Assertion (A) and Reason (R) are true, but Reason (R) is not correct explanation of Assertion (A).
  • Assertion (A) is true, but Reason (R) is false.
  • Assertion (A) is false, but Reason (R) is true.
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Understand what is being asked.
We must check whether Assertion (A), that a median of 54 follows from a mode of 50 and a mean of 56, is true, and whether Reason (R) correctly explains it. Let us use a different, equally valid form of the empirical relationship between mean, median and mode.

Step 2: Recall an equivalent form of the empirical relation.
The standard relation is $\text{Mode}=3\,\text{Median}-2\,\text{Mean}$. This can be rearranged into another common form used in some textbooks:
\[ \text{Mean} - \text{Mode} = 3(\text{Mean}-\text{Median}) \]
Step 3: Check Assertion (A) using this form.
Substitute Mean $=56$ and Mode $=50$:
\[ 56 - 50 = 3(56-\text{Median}) \]
\[ 6 = 3(56-\text{Median}) \]
Divide both sides by 3:
\[ 2 = 56 - \text{Median} \]
\[ \text{Median} = 56-2 = 54 \]
This matches the value given in Assertion (A), so Assertion (A) is true.

Step 4: Check Reason (R).
Reason (R) claims $\text{Median}=\frac{1}{3}(\text{Mode}-2\,\text{Mean})$. Rearranging our correct relation $\text{Mode}=3\,\text{Median}-2\,\text{Mean}$ for the median gives:
\[ \text{Median} = \frac{1}{3}(\text{Mode}+2\,\text{Mean}) \]
This has a plus sign, not the minus sign written in Reason (R), so Reason (R) is false.

Final Answer:
Assertion (A) is true and Reason (R) is false, matching option (C).
\[ \boxed{\text{Option (C)}} \]
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