Question

Arrange the given events to correct sequence in relation to translation:
A. Adenylation of amino acid and aminoacyl-tRNA charging.
B. Formation of Peptide bond.
C. Recruitment of ribosome to the mRNA.
D. Correct positioning of charged tRNA into the P-site of the ribosome.
Choose the most appropriate answer from the options given below:

• A. A, B, C, D
• B. A, C, D, B
• C. B, A, D, C
• D. C, B, D, A

Hint:

Think of translation like building with LEGOs:

\textbf{A (Charging):} Get your specific LEGO bricks (amino acids) and attach them to the delivery trucks (tRNA).
\textbf{C (Recruitment):} Bring the workbench (ribosome) to the blueprint (mRNA).
\textbf{D (Positioning):} The first delivery truck (initiator tRNA) parks at the starting position (P-site).
\textbf{B (Peptide bond):} The next truck arrives, and you connect the LEGO bricks. \end{itemize}

Answer 1

The Correct Option is B

Step 1: Understanding the Concept:
The question requires identifying the correct order of key events in protein synthesis (translation).

Step 2: Detailed Explanation of the Sequence:
1. A. Adenylation of amino acid and aminoacyl-tRNA charging: This is essential for translation. Aminoacyl-tRNA synthetase attaches each tRNA to its corresponding amino acid, a process occurring continuously in the cytoplasm before tRNA use.
2. C. Recruitment of ribosome to the mRNA: This initiates translation. The small ribosomal subunit binds to mRNA and scans for the start codon (AUG).
3. D. Correct positioning of charged tRNA into the P-site of the ribosome: After the start codon is located, the initiator tRNA (carrying methionine), already charged (Step A), binds to the ribosome's P-site, completing the initiation complex.
4. B. Formation of Peptide bond: This is the initial step in elongation. A second charged tRNA enters the A-site, and the ribosome forms a peptide bond between the amino acid in the P-site (methionine) and the new amino acid in the A-site. This cycle of tRNA entry, peptide bond formation, and translocation repeats.

Step 3: Final Answer:
The correct sequence is A \(\rightarrow\) C \(\rightarrow\) D \(\rightarrow\) B, corresponding to option (B).