Question:medium

Arrange the following in increasing order of focal length of a given lens. (A) \(f_V\) -- focal length for violet colour (B) \(f_B\) -- focal length for blue colour (C) \(f_Y\) -- focal length for yellow colour (D) \(f_R\) -- focal length for red colour Choose the correct answer from the options given below:

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For a lens, \[ f\propto \frac{1}{(\mu-1)} \] Higher refractive index implies smaller focal length. Therefore, violet light has the minimum focal length and red light has the maximum focal length.
Updated On: Jun 11, 2026
  • (A), (B), (C), (D)
  • (A), (B), (D), (C)
  • (C), (D), (B), (A)
  • (D), (C), (B), (A)
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The Correct Option is A

Solution and Explanation


Step 1:
Arrange the colours according to refractive index. \[ \mu_V>\mu_B>\mu_Y>\mu_R \]

Step 2:
Arrange the focal lengths. Since \[ f\propto \frac{1}{(\mu-1)} \] the focal length will be smallest for violet light and largest for red light. \[ f_V<f_B<f_Y<f_R \]

Step 3:
Write the increasing order. \[ (A)<(B)<(C)<(D) \] \[ { f_V<f_B<f_Y<f_R } \] Hence, the correct option is \[ {(A)} \]
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