Question:medium

Arrange products formed during payoff phase of the six-carbon glucose breakdown in correct sequence.
(A) 3-Phosphoglycerate
(B) Glyceraldehyde 3-phosphate
(C) Phosphoenolpyruvate
(D) 1,3-Bisphosphoglycerate

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In the payoff phase of glycolysis, high-energy intermediates are produced which contribute to ATP formation.
Updated On: Mar 1, 2026
  • (A), (C), (B), (D)
  • (C), (B), (D), (A)
  • (D), (A), (C), (B)
  • (B), (D), (A), (C)
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Glucose Breakdown.
Glycolysis involves the breakdown of glucose (a six-carbon molecule) into two pyruvate molecules.
The payoff phase of glycolysis generates ATP and key intermediates.

Step 2: Intermediate Sequence Verification.
- (A) 3-Phosphoglycerate: Formed when ATP is consumed to convert 1,3-bisphosphoglycerate to 3-phosphoglycerate.
- (C) Phosphoenolpyruvate: Generated from 2-phosphoglycerate by enolase; subsequently converted to pyruvate.
- (B) Glyceraldehyde 3-phosphate: A product of fructose-1,6-bisphosphate cleavage, contributing to further ATP synthesis.
- (D) 1,3-Bisphosphoglycerate: Produced following the oxidation of glyceraldehyde 3-phosphate.

Step 3: Final Sequence.
The correct order of these intermediates is (A), (C), (B), (D).

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