Question:medium

Aniline in a set of reactions yielded a product D.
 
Aniline


The structure of the product D would be:

Updated On: Apr 29, 2026
  • C6H5CH2NH2

  • C6H5NHCH2CH3

  • C6H5NHOH

  • C6H5CH2OH

Show Solution

The Correct Option is D

Solution and Explanation

  1. Let's analyze the sequence of reactions starting from aniline (C_6H_5NH_2).
  2. The first reaction involves NaNO2/HCl, which converts aniline to a diazonium salt. This step is represented as follows:
    C_6H_5NH_2 + NaNO_2 + HCl \rightarrow C_6H_5N_2^+Cl^− + H_2O + NaCl
    The product formed is benzene diazonium chloride.
  3. The second reaction with CuCN converts the diazonium salt into cyanobenzene (C_6H_5CN):
    C_6H_5N_2^+Cl^− + CuCN \rightarrow C_6H_5CN + N_2 + CuCl
  4. The next step involves the reduction of the cyano group using H2/Ni to form benzylamine (C_6H_5CH_2NH_2):
    C_6H_5CN + 2H_2 \rightarrow C_6H_5CH_2NH_2
    However, in this series of reactions, this is incorrect according to the provided image.
  5. The final step involves reacting the product with HNO2 to replace the amino group with a hydroxyl group, forming benzyl alcohol (C_6H_5CH_2OH):
    C_6H_5CH_2NH_2 + HNO_2 \rightarrow C_6H_5CH_2OH + N_2 + H_2O

The series of reactions thus results in the formation of benzyl alcohol. Therefore, the structure of product D is C6H5CH2OH.

Chemical Reaction Series

Other options represent different chemical structures that are not formed in this specific series of reactions.

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