Question:medium

Angular shape of ozone molecule consist of:

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Even though the true structure of ozone is a resonance hybrid where both O-O bond lengths are equal, the total count of localized $\sigma$ and $\pi$ bonds in its valid Lewis representations remains 2 $\sigma$ bonds and 1 $\pi$ bond.
Updated On: Jun 2, 2026
  • 1 sigma and 2 pi-bonds
  • 2 sigma and 2 pi-bonds
  • 1 sigma and 1 pi-bonds
  • 2 sigma and 1 pi-bonds
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The Correct Option is D

Solution and Explanation

Step 1: Draw ozone.
Ozone, $O_3$, has a central oxygen joined to two end oxygens. The shape is bent because of a lone pair on the middle atom.

Step 2: Identify the two bonds.
In the Lewis picture the centre oxygen forms one single bond to one end atom and one double bond to the other end atom.

Step 3: Count sigma and pi.
A single bond is one sigma. A double bond is one sigma plus one pi. Adding up:
\[ \sigma = 1 + 1 = 2, \quad \pi = 1 \]

Step 4: Final count.
So ozone has 2 sigma bonds and 1 pi bond.
\[ \boxed{2\ \sigma \text{ and } 1\ \pi \text{ bonds}} \]
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