Question:medium

An oil drop of charge q and mass m is in equilibrium in an electric field E. The charge of the oil drop is

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This is the fundamental principle behind Millikan's oil-drop experiment used to determine the elementary charge. Balancing forces is key to solving such equilibrium problems.
Updated On: Apr 21, 2026
  • $q = \frac{mg}{E}$
  • $q = \frac{E}{mg}$
  • $q = \frac{mg}{2E}$
  • $q = \frac{mg}{4E}$
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The Correct Option is A

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