Question:medium

An object is dropped from a certain point $A$ at a height 'h' from the ground. During its journey straight downwards, the object passes points $B$ and $C$ such that the ratio of time taken $t_1$ to cover $A B$ and $t_2$ to cover $B C$ is $1 : (\sqrt{2}-1)$. What is the ratio of distances $A B : B C$?

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For any object dropping from rest, the times taken to cover consecutive equal distances are always in the specific ratio: $1 : (\sqrt{2}-1) : (\sqrt{3}-\sqrt{2}) : \dots$ Since the provided times match this exact pattern, the distances must be equal!
Updated On: May 16, 2026
  • $\sqrt{2} : 1$
  • $(\sqrt{2}-1) : 1$
  • $1 : 1$
  • $1 : \sqrt{2}$
Show Solution

The Correct Option is C

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