Question:medium

An infinite line charge of uniform linear charge density $\lambda$ is placed along the $z$-axis. The work done in moving a charge $q$ from $(a,\,0,\,0)$ to $(2a,\,0,\,0)$ is:

Show Hint

The potential of an infinite line charge varies as $\ln r$ (not $1/r$), because its field falls off as $1/r$. So work done depends only on the ratio of distances, not their absolute values.
Updated On: May 16, 2026
  • $\dfrac{q\lambda}{2\pi\varepsilon_0}\ln 2$
  • $\dfrac{q\lambda}{4\pi\varepsilon_0}\ln 2$
  • $\dfrac{q\lambda}{2\pi\varepsilon_0}\ln\!\left(\tfrac{1}{2}\right)$
  • zero
Show Solution

The Correct Option is A

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