Question

An inductance of negligible resistance, whose reactance is \(120\) \(\Omega\) at \(200\) Hz is connected to a \(240\) V, \(60\) Hz Power line. The current in the inductor is

• A. \(6.66\) A
• B. \(6.60\) A
• C. \(5.45\) A
• D. \(54.5\) A

Hint:

Inductive reactance is proportional to frequency. Find the reactance at 60 Hz and apply Ohm's law.

Answer 1

The Correct Option is A

Step 1: Find L
$L=\dfrac{120}{2\pi\times200}$ H.

Step 2: New Reactance
At 60 Hz, $X_L=2\pi\times60\times L=36\ \Omega$.

Step 3: Result
$I=\dfrac{240}{36}\approx6.66$ A, option (A).

Final Answer:
The current drawn is about 6.66 A. \[ \boxed{\text{(A) }6.66\text{ A}} \]