The inductive reactance of a coil is \(R\ \Omega\). If the inductance of a coil is doubled and frequency of a.c. supply is also doubled then the new inductive reactance will be
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Inductive reactance \(X_L = \omega L = 2\pi f L\). It is directly proportional to both frequency and inductance.
Step 1: Understand the question. A coil has inductive reactance $R$. The inductance is doubled and the supply frequency is also doubled. We find the new reactance. Step 2: Recall the reactance formula. Inductive reactance is \[ X_L = 2\pi f L, \] where $f$ is frequency and $L$ is inductance. Step 3: Note the original value. Originally $X_L = 2\pi f L = R$. Step 4: Apply the changes. New frequency is $2f$ and new inductance is $2L$, so \[ X_L' = 2\pi(2f)(2L). \] Step 5: Simplify. \[ X_L' = 4\times(2\pi f L) = 4R. \] Step 6: State the answer. The new inductive reactance is $4R$. \[ \boxed{X_L' = 4R} \]