Question

An ideal gas expands by performing 200 J of work, during this internal energy increases by 432 J. What is enthalpy change?

• A. 200 J
• B. 232 J
• C. 432 J
• D. 632 J

Hint:

Logic Tip: Enthalpy change ($\Delta H$) represents the total heat transferred at constant pressure ($q_p$). Using the first law $\Delta U = q + w$, where $w = -200 \text{ J}$ (expansion work is lost energy) and $\Delta U = +432 \text{ J}$, we get $432 = q_p - 200 \implies q_p = 632 \text{ J}$. Since $\Delta H = q_p$, $\Delta H = 632 \text{ J}$.

Answer 1

The Correct Option is D