Question:medium
An equilateral triangle is inscribed in the circle x²+y²=a² with one of the vertices at (a,0). What is the equation of the side opposite to this vertex?
An equilateral triangle is inscribed in the circle x²+y²=a² with one of the vertices at (a,0). What is the equation of the side opposite to this vertex?
Show Hint
For an equilateral triangle in a circle, opposite side lies at distance a/2 from the center.
Updated On: Mar 20, 2026
- \(2x+a=0\)
- \(x+a=0\)
- \(3x-2a=0\)
- 3x-2a=0
Show Solution
The Correct Option is A
Solution and Explanation
Was this answer helpful?
0
Top Questions on Circles
- In the given figure, O is the centre of the circle. PQ and PR are tangents. Show that the quadrilateral PQOR is cyclic.
- In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :
- In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle OAB = 15^\circ \), then \( \angle APB \) equals :
- PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.
- Want to practice more? Try solving extra ecology questions todayView All Questions